WebNov 25, 2024 · The student-wise average marks are achieved in this manner. Syntax: SELECT COLUMN_NAME1,AVG(COLUMN_NAME2) AS ALIAS FROM TABLE_NAME … WebJun 28, 2016 · SELECT student_code, name FROM students WHERE marks = (SELECT MAX(marks) FROM students GROUP BY subject_code); For a start, the GROUP BY clause …
(1) Prachi has given the following command to obtain the highest marks …
WebSOLUTION. Aggregate functions are functions that take a collection (a set or multiset) of values as input and return a single value. The input to sum and avg must be a collection of numbers, but the other operators can operate on collections of … WebQuestion 8. The STUDENT information in a university stored in the relation STUDENT (Name, SEX, Marks, DEPT_Name) Consider the following SQL Query SELECT DEPT_Name from STUDENT where SEX = 'M' group by DEPT_Name having avg (Marks)>SELECT avg (Marks) from STUDENT. It Returns the Name of the Department for which: A. genshin windblume\u0027s breath
How to Compute the Average of a Column of a MySQL Table ... - GeeksForGeeks
WebJul 22, 2016 · SELECT AVG(average) FROM ( SELECT student_id, AVG(CA_total) -- assuming CA_total and term_total are not null FROM score_entry GROUP BY student_id ) AS T will do . Share. Improve this answer. Follow ... A average Mark overall for all of one student subjects. Hot Network Questions WebMay 29, 2024 · What is asked is to find the average marks for each student comprised by the total of the marks divided by their count. How should the query look like to achieve this, since the AVG function is an aggregate one that is retrieving the vertical average column-wise but not the horizontal. WebOct 14, 2015 · You need to use the the .aggregate () method and the $avg accumulator operator. var average = db.students.aggregate ( [ { "$group": { "_id": "null", avg: { "$avg": "$score"} }} ]).toArray () [0] ["avg"]; Then use the .find () method db.students.find ( { "score": { "$gt": average } }) Share Follow answered Oct 14, 2015 at 14:28 styvane chris cross song think of laura